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             (my)SQL question
 Posted 15 Aug 2001  21:29:48 
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  15 Aug 2001  21:29:48 Mark Labordus posted: 
 This is what I have:SELECT ROUND((TO_DAYS(NOW())-TO_DAYS(birthdate))/365) as age, if(gender = 'M', COUNT(*), 0) as male, if (gender = 'F', COUNT(*), 0) as female
FROM users
GROUP BY age, gender
This is the result:
age, male, female
20 , 12 , 0
21 , 0 , 3
24 , 8 , 0
24 , 0 , 6
What I want is that the last two results are shown together, I mean like this:
24, 8, 6
DOes anyone know how to do this?
Replies
 Replied 15 Aug 2001  23:40:22 
   15 Aug 2001  23:40:22 Joel Martinez replied: 
  Question Answered on the Dreamweaver Ultradev Forum.
PS. Please try to avoid crossposting <img src=../images/dmxzone/forum/icon_smile.gif border=0 align=middle>
Joel Martinez
----------
set rs = conn.execute("SELECT answer FROM brain WHERE question = "& forumPost &"
 
  PS. Please try to avoid crossposting <img src=../images/dmxzone/forum/icon_smile.gif border=0 align=middle>
Joel Martinez
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set rs = conn.execute("SELECT answer FROM brain WHERE question = "& forumPost &"
 Replied 15 Aug 2001  23:45:54 
   15 Aug 2001  23:45:54 Mark Labordus replied: 
  Sorry about that.. <img src=../images/dmxzone/forum/icon_smile.gif border=0 align=middle>
  
  